Article View: sci.physics
Article #5652Re: History of AC vs DC Power
From: Francois Yergeau
Date: Thu, 19 Nov 1992 16:31
Date: Thu, 19 Nov 1992 16:31
48 lines
3101 bytes
3101 bytes
In article <1992Nov18.204405.29722@mksol.dseg.ti.com> mccall@mksol.dseg.ti.com (fred j mccall 575-3539) writes: >In <1992Nov11.154425.8399@speedy.aero.org> steve@pepe.aero.org (Steve Sedlacek) writes: >>A question came up at lunch yesterday: Why is our power system completely >>AC? > >Well, actually it isn't. Isn't there some stupid rule that puts large >taxes on AC power transmission across state lines? I seem to remember >that there is, and that what the power companies do is convert the >power to DC on the transmission side of the line, send it across (tax >free), and then change it back to AC on the other side for further >transmission (a process referred to as 'wheeling', if I'm remembering >correctly). Apart from possible taxes, there's a good, physical reason to go to DC on occasion: grid synchronization. Take the situation of state A exporting power to state B; just imagine what would result if the power fed by A were 180 degrees out of phase with A's grid: big trouble! If you don't use AC->DC->AC as a "phase buffer", you need to keep synchronized the grids of all states that want to be connected together, which is pretty hard on a continental scale. To deal with that problem, Hydro-Quebec recently built a high-voltage DC line from James bay right down to the U.S. border, for the express purpose of exporting power to New-England. As far as I know, the DC->AC converter is north of the border, so that the power is exported as AC; only this one converter, however, needs to be synchronized with the New-England grid. >Even with the power losses involved in the two changes >and the expense of the 'wheeling' stations, it works out to still be >cheaper than paying the tax. For a long line, these losses and costs can be offset by the higher carrying capacity of the line: the power carried is P = V_rms.I_rms; in an AC line, the insulators have to be able to stand the peak voltage V_max = V_rms*sqrt(2); in a DC line, V_max = V_rms, so for the same line you can jack up the voltage and carry more power, or you can build a less expensive line to carry the same power. Disclaimer: I'm no engineer, so if I overlooked some important practical limitations in the above, please limit your flames to the mild variety. -- Francois Yergeau (yergeau@phy.ulaval.ca) | De gustibus et coloribus Centre d'Optique, Photonique et Laser | non disputandum Departement de Physique | -proverbe scolastique Universite Laval, Ste-Foy, QC, Canada |
Technical Details
Message-ID:
<1992Nov19.163117.10355@cerberus.ulaval.ca>Path:
arc1-ca.pugleaf.net!sparky!uunet!utcsri!newsflash.concordia.ca!cerberus.ulaval.ca!yergeauReferences:
<1992Nov11.154425.8399@speedy.aero.org> <1992Nov18.204405.29722@mksol.dseg.ti.com>Show Full Headers
Complete Article Headers
Newsgroups: sci.physics Path: arc1-ca.pugleaf.net!sparky!uunet!utcsri!newsflash.concordia.ca!cerberus.ulaval.ca!yergeau From: yergeau@phy.ulaval.ca (Francois Yergeau) Subject: Re: History of AC vs DC Power Message-ID: <1992Nov19.163117.10355@cerberus.ulaval.ca> Keywords: alternating current, direct current Sender: news@cerberus.ulaval.ca Nntp-Posting-Host: 132.203.76.4 Organization: Universite Laval, Quebec References: <1992Nov11.154425.8399@speedy.aero.org> <1992Nov18.204405.29722@mksol.dseg.ti.com> Date: Thu, 19 Nov 1992 16:31:17 GMT Lines: 48