🚀 go-pugleaf

In article <1495@wasatch.UUCP> ch-tkr@wasatch.UUCP (Timothy K Reynolds) writes:
>            No 2.45Mev neutrons were detected.  He speculated that these
>            neutrons may be consumed by reaction with Li:
>
>                        7Li + n + 2.45MeV ---> 3T + 3He + n
>                           6Li + n ---> 3T +3He + 4.5MeV

	Neither of these equations is balanced -- the first contains 3 protons
and 5 neutrons on the left as opposed to 3 protons and 4 neutrons on the
right; the second contains 3 protons and 4 neutrons on the left as opposed to
3 protons and 3 neutrons on the right.  Also, are you sure the second reaction
is supposed to be exothermic?  I think I have seen these before, but I can
only remember the first one with any degree of accuracy:

	(7)Li + n --> (3)H + (4)He + n

where the neutron comes out slower than it went in (thus supplying the energy
for the reaction).  I can't remember whether the second reaction should be

	(6)Li + n --> (3)H + (4)He

or

	(6)Li + n --> (3)H + (3)He + n

with the neutron again coming out slower than it went in.  I saw these
equations (obviously only one version of the second one, but I can't remember
which one) in some report on conventional fusion experiments discussing ways
to breed tritium.  (I think this report was from the Princeton Plasma Fusion
Physics Laboratory, but couldn't swear to that.)

	My other question is:  these people used a cell with palladium and
platinum electrodes and heavy water.  Where would the lithium come from?  I
didn't hear any mention of lithium in the electrodes or in the solution
before this article that I am replying to.

-- 
|  Lucius Chiaraviglio   |  ARPA:  chiaravi@silver.bacs.indiana.edu
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