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Article #8520Re: evolution?(please read)
From: William Tivol
Date: Mon, 05 May 1997 00:00
Date: Mon, 05 May 1997 00:00
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Christopher Carrell (cjc@pandora.bio.purdue.edu) wrote: : Your conclusion is correct, but I have to nitpick about the definition of equilibrium. : The equilibrium constant of some reaction is equal to the ratio of the forward : rate and the reverse rate of that reaction. If forward and backward rates are : equal, the equilibrium constant is 1. In which case, we'd never talk about : such-and -such a reaction is driven by ... at any rate, living organisms are : _not_ in a state of equilibrium, but they can't get too far from it, either. Dear Chris, I'll see your nit and raise you a nit. The reaction rates are de- termined by both the forward and backward rate constants and the activities of the constituents of the reactions. When the activities are equal to the concentrations, we have for A + B -> C + D that the forward reaction rate is k(f)[A][B] and the backward rate is k(b)[C][D], at equilibrium, these rates are equal, and the equilibrium constant, k(f)/k(b) = K, is [C][D]/[A][B]. Yours, Bill Tivol
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X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: 106bde,e5a72eede1eb5b86 X-Google-Attributes: gid106bde,public X-Google-Thread: 10b271,e5a72eede1eb5b86 X-Google-Attributes: gid10b271,public X-Google-Thread: 10b363,e5a72eede1eb5b86 X-Google-Attributes: gid10b363,public From: tivol@news.wadsworth.org (William Tivol) Subject: Re: evolution?(please read) Date: 1997/05/05 Message-ID: <5klam5$69c@euclid.wadsworth.org> X-Deja-AN: 239646482 References: <5kdbv8$cvi@charity.ucr.edu> <336AABE5.7A7C@swbell.net> <5kg5cn$1a8a@nntp6.u.washington.edu> <5kg79v$8m1@mozo.cc.purdue.edu> Followup-To: sci.physics,talk.origins,bionet.biophysics Organization: Wadsworth Center, NY Health Dept. Newsgroups: sci.physics,talk.origins,bionet.biophysics