Article View: sci.physics
Article #8550Re: evolution?(please read)
From: Christopher Carrell
Date: Sat, 03 May 1997 00:00
Date: Sat, 03 May 1997 00:00
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3380 bytes
Following up on my own post, but it has to be done... In article <5kg79v$8m1@mozo.cc.purdue.edu> cjc@pandora.bio.purdue.edu (Christopher Carrell) writes: >In article <5kg5cn$1a8a@nntp6.u.washington.edu> fujimoto@u.washington.edu (Bryant Fujimoto) writes: >> >>"pparso39@swbell.net" <pparso39@swbell.net> writes: >> >> >>>john baez wrote: >>>> >>>> In article <3369749D.3D21@midusa.net>, T. Haug <tjhaug@midusa.net> wrote: >>>> >John: >>>> >How do you define equilibrium? >>>> >>>> In physics (and I'm posting from sci.physics), "equilibrium" is >>>> a condition in which a physical system remains in the same state >>>> as time passes. According to this definition a sleeping dog is >>>> not in equilibrium, because while it might look static to the casual >>>> observer, it is actually breathing, metabolizing, pumping out heat >>>> into the environment, and so on, and eventually it will wake up >>>> and walk off. By this definition, living systems are never in >>>> equilibrium; you only reach equilibrium when you die and completely >>>> decompose. >>> No. Equillibrium is a dynamic state. For example, we take in air, >>>water, and nutrients, which become components of our bodies, which >>>give off waste products. That is equillibrium. The body stays the >>>same, more or less, but the actual materials move through the system. >> >>At equilibrium, the forward and backwards rates of all processes >>are equal. For an living organism, this would mean that the rate >>at which it takes in air, water, and nutrients is equal to the >>rate at which it gives off air, water and nutrients. Also the >>rate at which it gives off waste products is equal to the rate at >>which it takes in those waste products. That would be equilibrium, >>however, that is not what occurs in any living organism. > >Your conclusion is correct, but I have to nitpick about the definition of equilibrium. >The equilibrium constant of some reaction is equal to the ratio of the forward >rate and the reverse rate of that reaction. If forward and backward rates are >equal, the equilibrium constant is 1. In which case, we'd never talk about >such-and -such a reaction is driven by ... at any rate, living organisms are >_not_ in a state of equilibrium, but they can't get too far from it, either. Braaaackkk!!! This is a pile of you-know-what from me. Of course Bryant is correct and I'm bloody wrong. It's not rate ratio that's the equilibrium constant; it's the rate constant ratio. What an idiotic brain-cramp by me. I thought I knew better. Sorry to take up your time with my occasional idiocies. Chris
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X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: 10b271,e5a72eede1eb5b86 X-Google-Attributes: gid10b271,public X-Google-Thread: 10b363,e5a72eede1eb5b86 X-Google-Attributes: gid10b363,public X-Google-Thread: 106bde,e5a72eede1eb5b86 X-Google-Attributes: gid106bde,public From: cjc@pandora.bio.purdue.edu (Christopher Carrell) Subject: Re: evolution?(please read) Date: 1997/05/03 Message-ID: <5kgcrp$gae@mozo.cc.purdue.edu> X-Deja-AN: 239177051 References: <336AABE5.7A7C@swbell.net> <5kg5cn$1a8a@nntp6.u.washington.edu> <5kg79v$8m1@mozo.cc.purdue.edu> Followup-To: talk.origins Organization: Purdue University, Dept. of Biological Sciences Newsgroups: sci.physics,talk.origins,bionet.biophysics