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Article #84

Re: estimation performance of independant estimators

#84
From: Robert Israel
Date: Sun, 08 Jun 2003 20:53
34 lines
2180 bytes
In article <242be6f5.0306081036.7e5fcaf1@posting.google.com>,
Ray Koopman <koopman@sfu.ca> wrote:

>To avoid confusion with the expected value operator E, 
>call the estimates X1 and X2. Then we have 
>E(X1|RV) = RV, Var(X1|RV) = V1, 
>E(X2|RV) = RV, Var(X2|RV) = V2, 
>with X1|RV independent of X2|RV. 
>Let Xcomb = P1*X1 + P2*X2, where 
>P1 = (1/V1)/(1/V1 + 1/V2), 
>P2 = (1/V2)/(1/V1 + 1/V2). 
>Then E(Xcomb|RV) = RV, 
>and Var(Xcomb|RV) = V1*V2/(V1+V2), 
>which is less than both V1 and V2. 
>But note that V1 and V2 must be known 
>(as opposed to estimated).


But using reasonably good estimates for V1 and V2 will probably still 
work.

Say Xcomb = t X1 + (1-t) X2

Var(Xcomb|RV) = t^2 V1 + (1-t)^2 V2

which is less than both V1 and V2 as long as

max(0,(V2-V1)/(V1+V2)) < t < min(1,(2 V2)/(V1+ V2))


Robert Israel                                israel@math.ubc.ca
Department of Mathematics        http://www.math.ubc.ca/~israel 
University of British Columbia            
Vancouver, BC, Canada V6T 1Z2
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From: israel@math.ubc.ca (Robert Israel)
Newsgroups: sci.stat.math,sci.math,bln.net.statistik,bln.sci.mathematik
Subject: Re: estimation performance of independant estimators
Date: 8 Jun 2003 20:53:57 GMT
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