🚀 go-pugleaf

RetroBBS NetNews Server

Inspired by RockSolid Light RIP Retro Guy

Article View: uk.education.maths
Article #12

Re: Area under a graph !help!

#12
From: Robert Simon Martin
Date: Wed, 08 Mar 2000 00:00
17 lines
1626 bytes
>Hi I've got my GCSE coursework due in on Monday,
>and I have no idea what the formula for the area under
>a curved graph is, eg. area when the x-axis ranges for 0-4,
>in the graph of the function y=x^2 (y=x squared)

First you need to *integrate* y=x^2, you do this by increasing
the power by 1 and dividing by the new power, so I=(x^3)/3. Now
you have to work out the value of this expression when x=4 and
subtract the value where x=0, this gives the area. ie.

A=(4^3)/3-(0^3)/3=4*4*4/3=21.3333...

Rob


* Sent from RemarQ http://www.remarq.com The Internet's Discussion Network *
The fastest and easiest way to search and participate in Usenet - Free!
Technical Details
Message-ID: <14fbf8d8.dc379e3c@usw-ex0102-016.remarq.com>
Path: arc1-ca.pugleaf.net!unknown!not-for-mail
References: <8a6for$bcs$1@gxsn.com>

Show Full Headers
Complete Article Headers
X-Google-Language: ENGLISH,ASCII-7-bit
X-Google-Thread: f458d,2bcea0a7b99fab7
X-Google-Attributes: gidf458d,public
X-Google-Thread: 10d67e,2bcea0a7b99fab7
X-Google-Attributes: gid10d67e,public
X-Google-Thread: 102524,2bcea0a7b99fab7
X-Google-Attributes: gid102524,public
From: Robert Simon Martin <robNOroSPAM@rdale.force9.co.uk.invalid>
Subject: Re: Area under a graph !help!
Date: 2000/03/08
Message-ID: <14fbf8d8.dc379e3c@usw-ex0102-016.remarq.com>
X-Deja-AN: 594881882
References: <8a6for$bcs$1@gxsn.com>
Bytes: 670
X-Originating-Host: 193.113.185.167
X-Complaints-To: wrenabuse@remarq.com
X-Trace: WReNphoon2 952551395 10.0.2.16 (Wed, 08 Mar 2000 13:36:35 PST)
Organization: http://www.remarq.com: The World's Usenet/Discussions Start Here
NNTP-Posting-Date: Wed, 08 Mar 2000 13:36:35 PST
Newsgroups: uk.education.maths,alt.math,aus.mathematics
X-Wren-Trace: eODF7ez1svizsvvqxbLl6P72vuPq9qPzvKLs7Kfh8uC+v/Ovv/GmoL25sau/9qQ=