🚀 go-pugleaf

In article <ma-2703981552050001@mac89.maths.uwa.edu.au>, ma
<ma@maths.uwa.edu.au> writes
>Assume that a coordinate system of xyz-axes has been chosen. Then both a
>point P and its position vector \uparrow(OP) are represented by the same
>triple (a,b,c). Hence we are allowed to write P=(a,b,c)=\uparrow(OP), i.e.
>P=\uparrow(OP). With this simple notation, we have the simple formula:
>\uparrow(AB)=B-A.
>
>Question: DO you accept or reject the notation P=\uparrow(OP)?
>I DO need your public opinion URGENTLY. Please cast you vote, one way or
<snip>
>Dr. MA, Math Dept, UWA
>
>--------------------------------------------------------------------
>

For me, no. Not the same. The point p\in R^3 is completely and utterly
different from the vector v\in V_3(R), a vector space. 
:)
-- 
Oliver Low
HTTP://www.netmatrix.demon.co.uk
N.B. to reply, remove the obvious SPAM bit from the address.