🚀 go-pugleaf

 String a = "yes";
 String b = "ls";
 int aa = Integer.valueOf("foo").intValue();
 int bb = Integer.valueOf("bar").intValue();
 System.out.println("" + aa);
 System.out.println("" + bb);




try that








Luke Vanderfluit <luke@chipcity.com.au> wrote in message
news:3A63FC90.3C832EFA@chipcity.com.au...
> Hi
>
> I need help with this.
> Why doesn't the following code work?:
> I need to interpret a line of text as an integer.
>
> String a = "yes";
> String b = "ls";
> int aa = Integer.valueOf("foo").intValue();
> int bb = Integer.valueOf("bar").intValue();
> System.out.println(aa);
> System.out.println(bb);
>
> This throws a NumberFormatException
>
> How can I read a String as an Integer
>
> Can you help me please.
>
> Desperate,
> --
>   Luke Vanderfluit
>
>   Phone 61 8 8556 6112
>
>   Aldinga Beach, South Australia
>
>
>

The problem you are having is that neither "foo" or "bar" are able to be
parsed as an integer, or put in another way "foo" and "bar" cannot be
represented as an integer.  The Intger.valueOf(String) method is only
valid if the Sting is a String representation of an integer.  Try this;

String a = "yes";
String b = "ls";
String aaString = "25";
String bbString = "937";
try {
    int aa = Integer.valueOf(aaString).intValue();
    int bb = Integer.valueOf(bbString).intValue();
}
catch (numberFormatException e) {
    System.out.printLn(e.getLocalizedMessage());
}
System.out.println(aa);
System.out.println(bb);

Regards,

Ian Foster

Luke Vanderfluit wrote:

> Hi
>
> I need help with this.
> Why doesn't the following code work?:
> I need to interpret a line of text as an integer.
>
> String a = "yes";
> String b = "ls";
> int aa = Integer.valueOf("foo").intValue();
> int bb = Integer.valueOf("bar").intValue();
> System.out.println(aa);
> System.out.println(bb);
>
> This throws a NumberFormatException
>
> How can I read a String as an Integer
>
> Can you help me please.
>
> Desperate,
> --
>   Luke Vanderfluit
>
>   Phone 61 8 8556 6112
>
>   Aldinga Beach, South Australia

"Luke Vanderfluit" <luke@chipcity.com.au> wrote in message
news:3A63FC90.3C832EFA@chipcity.com.au...

> Why doesn't the following code work?:
>
> String a = "yes";
> String b = "ls";
> int aa = Integer.valueOf("foo").intValue();
> int bb = Integer.valueOf("bar").intValue();
> System.out.println(aa);
> System.out.println(bb);
>
> This throws a NumberFormatException

The integer value of "1" is 1. The integer value of "2" is 2. What do you
imagine the integer value of "foo" is? "foo" is not a number.

If you need to parse text values as numbers, maybe you need to look at
java.text.ChoiceFormat

Luke Vanderfluit <luke@chipcity.com.au> wrote in message
news:3A63FC90.3C832EFA@chipcity.com.au...
> Hi
>
> I need help with this.
> Why doesn't the following code work?:
> I need to interpret a line of text as an integer.
>
> String a = "yes";
> String b = "ls";
> int aa = Integer.valueOf("foo").intValue();
> int bb = Integer.valueOf("bar").intValue();
> System.out.println(aa);
> System.out.println(bb);
>
> This throws a NumberFormatException
>
> How can I read a String as an Integer
>
> Can you help me please.
>
> Desperate,
> --
>   Luke Vanderfluit
>
>   Phone 61 8 8556 6112
>
>   Aldinga Beach, South Australia
>
>
>

> Luke Vanderfluit <luke@chipcity.com.au> wrote ...
> > I need to interpret a line of text as an integer.
> >

Using what conversion?

> > String a = "yes";
> > String b = "ls";
> > int aa = Integer.valueOf("foo").intValue();
> > int bb = Integer.valueOf("bar").intValue();
> > System.out.println(aa);
> > System.out.println(bb);
> >
> > This throws a NumberFormatException

As well it should, since neither "foo" nor "bar" are valid integer values.
What integer value do you want to get back?  For one possible integer value,
you could use "foo".hashCode(), but that may not be what you want.  What
*do* you want?

Chris Smith

"Chris Smith" <cdsmith@twu.net> wrote in message
news:9f6i6i$h5d$0@dosa.alt.net...
> > Luke Vanderfluit <luke@chipcity.com.au> wrote ...
> > > I need to interpret a line of text as an integer.
> > >
>
> Using what conversion?
>
> > > String a = "yes";
> > > String b = "ls";
> > > int aa = Integer.valueOf("foo").intValue();
> > > int bb = Integer.valueOf("bar").intValue();
> > > System.out.println(aa);
> > > System.out.println(bb);
> > >
> > > This throws a NumberFormatException
>
> As well it should, since neither "foo" nor "bar" are valid integer values.
> What integer value do you want to get back?  For one possible integer
value,
> you could use "foo".hashCode(), but that may not be what you want.

You could also use Integer.parseInt("foo");


> What *do* you want?

"Carl Schodde" <schodde@ozemail.com.au> wrote ...
> You could also use Integer.parseInt("foo");
>

Well, the point of my post is that you can't.  The OP obviously want some
specific form of unusual generation of an integer value from text that it's
integral in nature.  The above will throw an exception, not convert a string
to an integer.

Chris Smith

See java.text.ChoiceFormat .

--
--------------------------------------------------------------
Sometimes he answers "Yes", sometimes "No", sometimes "Wait", and sometimes
he gives you something different.
You get the same set of responses praying to a rock.
http://www.users.bigpond.com/pmurray
ICQ: 26066755

"rastgoo" <rastgoo@thefreeinternet.co.uk.NOSPAM> wrote in message
news:3b16b1bd_3@news.bizonline.net...
>
> Luke Vanderfluit <luke@chipcity.com.au> wrote in message
> news:3A63FC90.3C832EFA@chipcity.com.au...
> > Hi
> >
> > I need help with this.
> > Why doesn't the following code work?:
> > I need to interpret a line of text as an integer.
> >
> > String a = "yes";
> > String b = "ls";
> > int aa = Integer.valueOf("foo").intValue();
> > int bb = Integer.valueOf("bar").intValue();
> > System.out.println(aa);
> > System.out.println(bb);
> >
> > This throws a NumberFormatException
> >
> > How can I read a String as an Integer
> >
> > Can you help me please.
> >
> > Desperate,
> > --
> >   Luke Vanderfluit
> >
> >   Phone 61 8 8556 6112
> >
> >   Aldinga Beach, South Australia
> >
> >
> >
>
>

try this:

String bb;

int xx = 2;

bb = String.valueOf(xx);

this will give the value of the xx var as a String object...

--this valueOf(int x) method is static so you don't need to instantiate a
String object to utilize it...

or, if you're trying to convert an int to a String, just use this:

Integer xx = new Integer(2);

xx.toString();

best.

kelbarnes.

"Paul Murray" <pmurray@nospam.bigpond.com> wrote in message
news:NEYR6.31881$hV3.53039@newsfeeds.bigpond.com...
> See java.text.ChoiceFormat .
>
> --
> --------------------------------------------------------------
> Sometimes he answers "Yes", sometimes "No", sometimes "Wait", and
sometimes
> he gives you something different.
> You get the same set of responses praying to a rock.
> http://www.users.bigpond.com/pmurray
> ICQ: 26066755
>
> "rastgoo" <rastgoo@thefreeinternet.co.uk.NOSPAM> wrote in message
> news:3b16b1bd_3@news.bizonline.net...
> >
> > Luke Vanderfluit <luke@chipcity.com.au> wrote in message
> > news:3A63FC90.3C832EFA@chipcity.com.au...
> > > Hi
> > >
> > > I need help with this.
> > > Why doesn't the following code work?:
> > > I need to interpret a line of text as an integer.
> > >
> > > String a = "yes";
> > > String b = "ls";
> > > int aa = Integer.valueOf("foo").intValue();
> > > int bb = Integer.valueOf("bar").intValue();
> > > System.out.println(aa);
> > > System.out.println(bb);
> > >
> > > This throws a NumberFormatException
> > >
> > > How can I read a String as an Integer
> > >
> > > Can you help me please.
> > >
> > > Desperate,
> > > --
> > >   Luke Vanderfluit
> > >
> > >   Phone 61 8 8556 6112
> > >
> > >   Aldinga Beach, South Australia
> > >
> > >
> > >
> >
> >
>
>

kelb <bkkelly@qwest.net> wrote:
> try this:
> 
> String bb;
> 
> int xx = 2;
> 
> bb = String.valueOf(xx);
> 
> this will give the value of the xx var as a String object...
> 
> --this valueOf(int x) method is static so you don't need to instantiate a
> String object to utilize it...
> 
> or, if you're trying to convert an int to a String, just use this:
> 
> Integer xx = new Integer(2);
> 
> xx.toString();

You seem to be presenting them as solutions to different problems, when 
actually they both solve *exactly* the same thing.

The second method, however, creates an Integer object unnecessarily.

I prefer String.valueOf (xx); myself.

-- 
Jon Skeet - skeet@pobox.com
http://www.pobox.com/~skeet
If replying to the group, please don't mail me at the same time