arithmetic Robak 0,(9)+{1+}0=1 Time Theory

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2 total messages Started by ksRobak Fri, 02 Jul 2004 16:06

#77

Author: ksRobak
Date: Fri, 02 Jul 2004 16:06

59 lines
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http://niusy.onet.pl/niusy.html?t=artykul&group=pl.sci.filozofia&aid=31516935

arithmetic Robak -- Time Theory
~~~~~~~~~~~~~~~~~~~~~~~~~
           1
1/3=0, (10/3)
           1    2
1/3=0, 3 (10/3)
           1 2    3
1/3=0, 3 3 (10/3)
           1 2 3    4
1/3=0, 3 3 3 (10/3)
           1 2 3 4    5
1/3=0, 3 3 3 3 (10/3)
           1 2 3 4 5 ...  Re1  <==  Re1 = N (max)
1/3=0, 3 3 3 3 3 ...(10/3)
                      n -> oo
1/3=3/10+3/10^2+3/10^3+...+3/10^(Re1-1)+(10/3)/10^Re1
1/3=0,(3)(10/3)
3*1/3=3*0,(3)(10/3)=0,(9)(30/3)=0,(9)(10)=1

1/Re1={1+}0=+0   <== +0 = PUNKT
Re1*{1+}0=1   ((~  oo*0=1 ))
A-A=0   <== 0 = (NC) = Arithmetic ZERO
PUNKT - (NC) =+0 - 0 = 1/Re1
__________________

1/3 +/- 3/10^n=3/10+...+(10/3)/10^Re1 +/- 3/10^n <== Re1=const
~~~~~~~~~~~~~~~~~~~~~~~~~~
PUNKT * a/b = +0 * a/b = {a/b+}0
~~~~~~~~~~~~~~~~~~~~~~~~~~
{a/b+}0 * Re1 = a/b
__________________

   1.  1/3=3/10+(1/3)/10
   2.  1/3=3/10+3/10^2 +(1/3)/10^2
   3.  1/3=3/10+3/10^2 +3/10^3+(1/3)/10^3
   n.  1/3=3/10+3/10^2 +3/10^3+...+3/10^n+(1/3)/10^n
Re1. 1/3=3/10+3/10^2 +3/10^3+...+3/10^Re1+(1/3)/10^Re1
              =3/10+3/10^2 +3/10^3+...+(10/3)/10^Re1

0,(3)+(10/3)/10^Re1=0,(3)(10/3)=1/3
__________________

n              N       1/N
1              1         1
2              2         1/2
3              3         1/3
4              4         1/4
5              5         1/5
...
Re1          Re1      +0
++++++++++++++++++  1/N + 2/3
Re1+1     (NC)      2/3

Edward Robak - Krakow, 2.06.2004 - Poland
"ksRobak" ed_robak@wp.pl  \|/  re:
--
Ipse dixit!

Re: arithmetic Robak 0,(9)+{1+}0=1 Time Theory

#78

Author: ksRobak
Date: Mon, 05 Jul 2004 14:30

20 lines
1608 bytes

"ksRobak" <ed_robak@interia.pl>
news:cc41c4$in2$2@nemesis.news.tpi.pl...

arithmetic Robak -- Time Theory by ksRobak (continue)
~~~~~~~~~~~~~~~~~~~~~~~~~
1/3 = 1/3 * 10/10 = (10/3) / 10 _|_ 10/3 = X
1/3 = X/10 = 0,X 

1/3 = 0,X = 9/30 + 1/30 = 3/10 + (10/3)/10^2 = 3/10 + X/10^2 = 0,3X
0,X = 0,3X
1/3 = 0,X = 0,3X = 0,33X = 0,3333...X = 0,(3)X = 0,(3)(10/3)

0,(3)(10/3) - 0,(3) = (10/3) / 10^Re1

Edward Robak ed_robak@wp.pl  \|/  re:
--
Ipse dixit!

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