🚀 go-pugleaf

Hi

From memory extractfilepath return the path of the exe name, which is equivelent to the GetModuleName.

I'll try it to make sure, but I pretty sure that is its behavior.

Thanks
Marc


"Vladimir Stefanovic" <antivari@po.sbb.co.yu> wrote:
>Look at ParamStr(0) or Application->ExeName.
>
>Example:
>   Path = ExtractFilePath( ParamStr(0) );
>or:
>   Path = ExtractFilePath( Application->ExeName );
>
>-- 
>Best regards,
>Vladimir Stefanovic
>"Marc" <bukwheat_NS@axess.com> wrote in message 
>news:4266bf60@newsgroups.borland.com...
>>
>> Hi
>>
>> I am having an issue with retrieving the directory from where
>> my application is started from, let me explain...
>>
>> GetModuleFileName and GetCurrentDirectory aren't cutting it for
>> me.  GetMod... retruns the location of my exe as expected as
>> for GetCurrentDirectory it works only when I am local on my
>> system.
>>
>> Results from GetCurrentDirectory executions:
>> My actual EXE resides on C:\program files\Somedirectory\Application.exe.
>> 1. From the RUN dialog box GetCurrentDirectory return the location where 
>> the EXE resides.
>> 2. I have a batch file located on my desktop from which I
>> execute the same command line as in the run command, in this
>> case I get my desktop folder as expected.
>> 3. Same batch file as the one on my desktop but this time I run
>> it off a shared network path (\\somePC\SomeDirectory\file.bat
>> in this case GetCurrectDirectory return C:\Windows.
>>
>> I have 2 questions, why C:\Windows and how can I have my
>> application return the network path?
>>
>> Thanks for the help.
>> Marc
>> 
>
>