🚀 go-pugleaf

yes I means to compare strings lexicographiclly.
I have a solution:

if (string1.compareTo(string2) == -1)   // string1 < string2
    {
         .... code .....
    }

if (string1.compareTo(string2) == 1)   // string1 > string2
    {
         .... code .....
    }

if (string1.compareTo(string2) == 0)   // string1 == string2
    {
         .... code .....
    }


Rob

"Alexander Petry" <alex_petry-nospam@web.de> schrieb im Newsbeitrag
news:87660d912w.fsf@nbook.wohnheim.uni-kl.de...
> On Thu, 20 Jun 2002, coff@online.no spake thusly:
>
> > You can not compare two strings using less-than or greater-than.
> > What are you trying to accomplish? compare the size or?
>
> I think, that he means how to compare strings lexicographically.
>
> >
> > On Thu, 20 Jun 2002 21:30:23 +0200, "Reiz" <RReiz@gmx.de> wrote:
> >
> >>How can I do it in Java
> >>
> >>If (String1 < String2) then
> >>    ...
> >>    code ....
> >>    ....
> >>end if
> >>
>
> Have a look at the java api of the String class. It says this:
>
> ,----[ compareTo(String s) method ]
> | compareTo
> |
> | public int compareTo(String anotherString)
> |
> | Compares two strings lexicographically. The comparison is based on
> | the Unicode value of each character in the strings. The character
> | sequence represented by this String object is compared
> | lexicographically to the character sequence represented by the
> | argument string. The result is a negative integer if this String
> | object lexicographically precedes the argument string. The result is a
> | positive integer if this String object lexicographically follows the
> | argument string. The result is zero if the strings are equal;
> | compareTo returns 0 exactly when the equals(Object) method would
> | return true.
> | ...
> |
> `----
>
>
> Alex