🚀 go-pugleaf

kellyc@nbnet.nb.ca,Internet writes:
>I am having problems with the following question. Could you please help
>me by showing me how it is worked out. I've been through my textbook and
>my mom has tried to figure it out..maybe I can help you in return in
>the 
>near future:

>Craig is one year less than twice as old as Colin. The sum of three
>times 
>Craig's age and twice Colins's age is 45. Find their ages.  The answer
>is
>Craig is 11 and Colin is 6. Please show me how they figured this out?
>I am knew at word problems..grade 10.

Let 2x-1 be Craig's age
Let x be Colin's age

3(2x-1)+2x=45
      6x-3+2x=45
             8x-3=45 
                  8x=48
	        x=6 (Colin's age)
	 2x-1=11 (Craig's age)

Craig is 11 and Colin is 6.