🚀 go-pugleaf

Kurt Watzka (watzka@stat.uni-muenchen.de) wrote:

: yang@math.umass.edu (Huayong Yang) writes:

: >void Swap(void** p1, void** p2)

: It is not allowed to dereference a void *, not is it necessary in
: this example.

I agree. But you forgot to give an answer to Huayong.
Please enlighten us with *your* solution to this problem.

The best I could directly think of is :

void swap(void ** x, void ** y)
{
	char * tmp;

	tmp = *( (char**)x );
	*( (char**)x ) = *( (char**)y );
	*( (char**)y ) = tmp;
}

You would call it for 
	SomeType * x, * y 
sth like
	swap((void**)&x,(void**)&y);
to avoid "incompatible pointer type"-warnings.

Best regards

	Claus