🚀 go-pugleaf

In article <DEHyMv.E4r@stdc.demon.co.uk>
           clive@demon.net "Clive D.W. Feather" writes:

>In article <DEG4C6.6Ao@polo.demon.co.uk>,
>John Winters <john@polo.demon.co.uk> wrote:
>> Surely 0x80000000L is only too big for a long int on a 32 bit machine
>> if you intend it to be interpreted as a positive number?  It fits in a
>> 32 bit signed int fine, and represents -2147483648.
>
>The C expression 0x80000000L is a way of writing the value 2147483648.
>It is always a positive value. Since it won't fit in a 32-bin long int,
>the language gives it the type unsigned long int.

It may be worth noting that all integer constants represent positive values
(perhaps there are theoretical circumstances where a character constant
could end up negative). In particular something like -1 is equivalent to
-(1) i.e. the integer constant 1 to which is applied the unary - operator.
The result is an integral constant expression with a negative value, not an
integer constant.

-- 
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Lawrence Kirby | fred@genesis.demon.co.uk
Wilts, England | 70734.126@compuserve.com
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