🚀 go-pugleaf

In article <rshapiro-0102960833080001@ipa.bbn.com>, rshapiro@bbn.com 
says...
>
>I need to reference a pointer to a member function within a template,
>where the class of the function is determined by the template parameter.
>
>class ATest {
[snip!]
>};
>
>template <class OBJECT>
>class Test {
>   // (a) This is what I want but it won't compile in CodeWarrior 8:
>   //typedef void (OBJECT::*ObjectMemberFunction)(void); 
>
>   // (b) This works but isn't what I want:
>   typedef void (ATest::*ObjectMemberFunction)(void); 
>   
[snip!]
>};     

I think the answer is NO.  A template is a cookie cutter for whatever you 
specify, but it doesn't assume any knowledge about what you specify 
beyond whether it is a class template or a function template.  In this 
case, knowing that a particular function is in the class (your desired 
typedef with the OBJECT::*ObjectMemberFunction... specification) is what 
is causing the problem.

When you specify a class the compiler knows about, namely ATest (i.e., 
ATest::*ObjectMemberFunction...) it is happy to oblige...

I dug this out of the C++ FAQ book, although it wasn't explicitly 
discussed.

So I might be wrong...
 
-- 
G. Patrick Sand
psand@eos.hitc.com
PatSand@aol.com
(301) 925-0791
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