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Article #13980Answer on problem?
From: Ron Stewart
Date: Thu, 25 Jan 1996 00:00
Date: Thu, 25 Jan 1996 00:00
48 lines
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2743 bytes
I'm trying to solve this problem but I don't get anywhere!? Can someone please
give me an answer to it? Thanx!
In addition to our kitchen remodel, we are also going to build a shed off
the back of the house to store the garden tools, lawn mower, and
motorcycle. It will be attached to the back of the mud room, and the roof
will have the same slope as the roof of the mud room.
The mud room roof has a 2" pitch. The "pitch" of a roof stands for how
many inches it rises for each foot it runs. (A 2" pitch isn't very steep
if you have a shingle roof, and is one reason why our roof leaks in a big
rain!)
I need to decide where to attach the shed to the mud room wall, so let's
work backwards. I want the shed to be 12 feet long, so it will run 12
feet out into the yard. I want the end wall to be 6' tall. How far up
the mud room wall will the shed roof need to be attached? (Explain your
answer! There are a lot of ways to figure this one out, so I want to know
how you did it.)
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mud room | --------
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| ?? |
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| shed | 6'
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___________________|_______________________________________________|
12'
The roof line of the mudroom is 12'6" off the ground. If I just continued
the roof of the shed from the roof of the mud room, how far out into the
yard would it go before it was 8' off the ground?
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X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: f4956,a7966ded951be04d,start X-Google-Attributes: gidf4956,public From: system@undersea.deesoft.wa.com (Ron Stewart) Subject: Answer on problem? Date: 1996/01/25 Message-ID: <4e6sbu$kfa@natasha.rmii.com> X-Deja-AN: 136434358 organization: Rocky Mountain Internet Inc. newsgroups: fj.sci.math