Re: [Q] 1/2 + cos t + cos 2t + ... = ?

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Article #14079

#14079

From: Kazuo Sano
Date: Wed, 29 Nov 1995 00:00

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$@$9$_$^$;$s!#0l2U=jD{@5$G$9!#(J

>  1/2 + cos(t)+ cos(2t)+...= (1/2)sin(n-1/2)t / sin(1/2)
>   $@!!!!!!!!!!!!!!!!!!!!!!!!(J= (1/2)[cos(n-1)t - cos(nt)] / (1-cost)

$@:8JU$O!"(J1/2 + cos(t)+ cos(2t)+...+ cos(n-1) $@$^$G$G$9!#(J

--
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        Kazuo Sano    faculty of ECoNomics    Fukui Pref. Univ.
         0776-61-6000(FAX:6014)    sano@antares.ecn.fpu.ac.jp
    -:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-

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X-Google-Language: Japanese,JIS
X-Google-Thread: f4956,59338ae7330974cd
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From: sano@antares.ecn.fpu.ac.jp (Kazuo Sano)
Subject: Re: [Q] 1/2 + cos t + cos 2t + ... = ?
Date: 1995/11/29
Message-ID: <SANO.95Nov29141133@antares.ecn.fpu.ac.jp>
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references: <SANO.95Nov29140840@antares.ecn.fpu.ac.jp>
organization: Fukui Prefectural University,Fukui,JAPAN
newsgroups: fj.sci.math

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