[Q] 1/2 + cos t + cos 2t + ... = ?

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Article #14078

#14078

From: Kazuo Sano
Date: Wed, 29 Nov 1995 00:00

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1/2 + cos(t)+ cos(2t)+...= (1/2)sin(n-1/2)t / sin(1/2)
 $@!!!!!!!!(J$@!!!!!!!!!!!!!!!!(J= (1/2)[cos(n-1)t - cos(nt)] / (1-cost)

$@$,J,$+$j$^$;$s!#$3$l$O%U!<%j%(5i?t$N<}B+$KI,(J$@MW$JDjM}$r(J
$@Aj2CJ?6QAmOBK!$K$h$C$FF3$/:]$K$G$F$/$kEy<0$G$9!#%R%s%H(J
$@$J$I$G$b7k9=$G$9$N$G$h$m$7$/$*4j$$$7(J$@$^$9!#(J



--
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        Kazuo Sano    faculty of ECoNomics    Fukui Pref. Univ.
         0776-61-6000(FAX:6014)    sano@antares.ecn.fpu.ac.jp
    -:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-:-

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From: sano@antares.ecn.fpu.ac.jp (Kazuo Sano)
Subject: [Q] 1/2 + cos t + cos 2t + ... = ?
Date: 1995/11/29
Message-ID: <SANO.95Nov29140840@antares.ecn.fpu.ac.jp>
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