🚀 go-pugleaf

I think I have found a bug in the builtin function calling sequence
for the sparc in gcc-1.35.  The following program:

main()
{
	int i;

	i = 3;

	printf("one is %d\n", i/3);
}

produces the following assembler code when compiled with "gcc -S":

gcc_compiled.:
.text
LC0:
	.ascii "one is %d\12\0"
	.align 4
.global _main
	.proc 1
_main:
	!#PROLOGUE# 0
	save %sp,-120,%sp
	!#PROLOGUE# 1
	mov 3,%o2
	st %o2,[%fp-20]
	call .div,0
	nop
	mov %o0,%o1
	sethi %hi(LC0),%o0
	or %lo(LC0),%o0,%o0
	mov %o1,%o1
	call _printf,0
	nop
L1:
	ret
	restore

and when run, produces the output:

one is 0

The problem seems to be that the arguments to the builtin function
".div" are never put in the output registers, therefore the ".div"
function returns 0.

Using Version 1.34 of gcc, the following code is produced:

gcc_compiled.:
.text
LC0:
	.ascii "one is %d\12\0"
	.align 4
.global _main
	.proc 1
_main:
	!#PROLOGUE# 0
	save %sp,-120,%sp
	!#PROLOGUE# 1
	mov 3,%o2
	st %o2,[%fp-20]
	ld [%fp-20],%o0
	mov 3,%o1
	call .div,0
	nop
	mov %o0,%o1
	sethi %hi(LC0),%o0
	or %lo(LC0),%o0,%o0
	mov %o1,%o1
	call _printf,0
	nop
L1:
	ret
	restore


which produces the correct result.

This seems only to be a problem for the sparc version; the 386 and
68020 versions seem to work fine.

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