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Article #2158Re: A very simple question on SED or AWK for a GURU, possibly a lisp script or emacs batch processing of many files
From: Alan Mackenzie
Date: Tue, 14 Jan 2003 22:54
Date: Tue, 14 Jan 2003 22:54
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gnuist006 <gnuist006@hotmail.com> wrote on 13 Jan 2003 16:03:15 -0800:
> Here is the type of lines I have in a file:
> junk label="junk1/junk2/junk3/.../junkn/" more junk
> I want to find every line that has
> label="..."
> pattern
> and then I want to replace every / by _ inside the
> quotes.
Sounds like awk could be your tool of choice. Using gawk:
cat file |
gawk 'BEGIN {FS = "\""; OFS = "\""}; /[a-zA-Z_0-9]+=/ {gsub("/", "_", $2)}; {print}'
(or something very like it) will do the job. Note: I haven't tested
this. The solution assumes that the "junk" at the beginning of each line
doesn't contain any "s.
I would guess that alternative solutions, whether in Emacs lisp or
perl or whatever would be much longer than this one-liner. The
newsgroup comp.lang.awk might be a better place to ask such questions.
Alternatively, email me if the above gawk program doesn't "quite" work,
or you want me to explain it.
> gnuist.
--
Alan Mackenzie (Munich, Germany)
Email: aacm@muuc.dee; to decode, wherever there is a repeated letter
(like "aa"), remove half of them (leaving, say, "a").
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From: Alan Mackenzie<none@example.invalid>
Newsgroups: gnu.misc.discuss,comp.lang.lisp,gnu.emacs.help
Subject: Re: A very simple question on SED or AWK for a GURU, possibly a lisp script or emacs batch processing of many files
Date: Tue, 14 Jan 2003 22:54:19 +0000
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