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Article #18

Re: tre serie (tres series)

#18
From: Ignacio Larrosa Cañestro
Date: Sat, 05 Nov 2011 10:27
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superpollo wrote:
> A = sum(1/((2n-1)(3n-1)),n,1,inf)

rq(3)pi/6 - ln(27/16)/2

> B = sum(1/((2n-1)(4n-1)),n,1,inf)

pi/4 - ln(2)/2  (esta es la m�s f�cil)

> C = sum(1/((3n-1)(4n-1)),n,1,inf)

3ln(3/4)/2 + pi(3 - rq(3))/6

Hoy estar� fuera todo el dia, ma�ana lo justifico si nadi4e lo ha hecho 
antes.


-- 
Saludos,

Ignacio Larrosa Ca�estro
A Coru�a (Espa�a)
ilarrosaQUITARMAYUSCULAS@mundo-r.com
http://www.xente.mundo-r.com/ilarrosa/GeoGebra/ 
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From: Ignacio Larrosa Cañestro <ilarrosaQUITARMAYUSCULAS@mundo-r.com>
Newsgroups: it.scienza.matematica,es.ciencia.matematicas
Subject: Re: tre serie (tres series)
Date: Sat, 5 Nov 2011 11:27:49 +0100
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