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Article #185Re: 5-2 problem
From: Philip Stromer
Date: Tue, 13 Oct 1992 03:24
Date: Tue, 13 Oct 1992 03:24
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Mika, I think you're miscalculating something. I count 17 ways to get hit with an indirect 6: The basic 11, plus 2/2, 3/3, 1/5, 5/1, 2/4, 4/2. I also count 17 ways to get hit by a 1 *and* 8 (which is the case if you leave the blot on 20 in your diagram. The basic 11 1's, plus 6 extra ways to reach 8: 2/2, 4/4, 2/6, 6/2, 3/5, 5/3. I would move 11/6, 8/6 in your position. O is behind in a running game, albeit slightly, and this closes the running game gap, provided that X does not safely cover his blot on 12. Remember, you both have 5-point boards, so X is in danger of losing here, too. Leave the blot on 20, and PRAY LIKE HELL that X doesn't roll a 1. --Philip Stromer-- (peewee@infoserv.com)
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Path: arc1-ca.pugleaf.net!sparky!uunet!infoserv!peewee From: peewee@infoserv.com (Philip Stromer) Newsgroups: rec.games.backgammon Subject: Re: 5-2 problem Keywords: Response to Mika Message-ID: <oNcksB1w163w@peewee> Date: Mon, 12 Oct 92 20:24:35 PDT References: <1992Oct12.124313.1@sara.cc.utu.fi> Organization: Moon Macrosystems Lines: 18