Thread View: sci.math.num-analysis
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Started by K.C.Goh
Fri, 22 Jan 1993 06:17
Exploiting Structure of Hamiltonian Matrices
Author: K.C.Goh
Date: Fri, 22 Jan 1993 06:17
Date: Fri, 22 Jan 1993 06:17
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Does anybody out there know of any numerical routines
for the computation of the eigenvalues of a Hamiltonian
matrix (or the zeros of a Hamiltonian Pencil) which exploit
=============
the Hamiltonian eigenvalue (zero) structure?
===========================================
For example, are there any numerical routines which produce
Paige and van Loan's Hamiltonian Schur form?
Thanks,
K.C. Goh
Re: Exploiting Structure of Hamiltonian Matrices
Author: Steven Smith
Date: Fri, 22 Jan 1993 13:44
Date: Fri, 22 Jan 1993 13:44
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goh@nyquist.usc.edu (K.C.Goh) writes:
> Does anybody out there know of any numerical routines
> for the computation of the eigenvalues of a Hamiltonian
> matrix (or the zeros of a Hamiltonian Pencil) which exploit
> the Hamiltonian eigenvalue (zero) structure?
See C. F. Van Loan (1984), A symplectic method for approximating all
the eigenvalues of a Hamiltonian matrix, Lin. Alg. Appl., 61, 233-252,
and the references therein. There is also more recent work by
Bunse-Gerstner et al. I have never encountered any public domain
software for these type of problems.
By the way, these papers define the symplectic group to be the group
of transformations leaving invariant the form
_ _ _
x y + x y + . . . + x y
1 1 2 2 n n
_ *
(y denotes the complex conjugate of y). This is really the group SO(n);
the symplectic group leaves invariant the form
x y + x y + . . . + x y .
1 1 2 2 n n
I don't know if this matters to you; they do this because the
Hermitian pops up in the (complex) Riccati equation.
Steven Smith
Re: Exploiting Structure of Hamiltonian Matrices
Author: David John Schneider
Date: Fri, 22 Jan 1993 14:28
Date: Fri, 22 Jan 1993 14:28
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smith@minerva.harvard.edu (Steven Smith) writes:
>
> By the way, these papers define the symplectic group to be the group
> of transformations leaving invariant the form
> _ _ _
> x y + x y + . . . + x y
> 1 1 2 2 n n
> _ *
> (y denotes the complex conjugate of y). This is really the group SO(n);
> the symplectic group leaves invariant the form
>
> x y + x y + . . . + x y .
> 1 1 2 2 n n
>
> I don't know if this matters to you; they do this because the
> Hermitian pops up in the (complex) Riccati equation.
>
Neither of these definitions correspond to the usual definition
of the invariant form for symplectic groups. For example,
Gilmore ("Lie Groups, Lie Algebras, and Some of Their Applications",
J. Wiley, 1974, chapter 2) defines symplectic groups as those
which preserve a bilinear antisymmetric form such as:
x y - x y + x y - x y + ...
1 n n 1 2 n-1 n-1 2
The forms mentioned above by Steve Smith are sesquilinear and
bilinear, respectively, and both are symmetric.
As mentioned by Steve Smith it may be that the authors are really
interested in the one of the non-compact groups SO^*(2N) or SU^*(2N),
the so-called "embedding groups". The appearance of these groups
is reasonable given the close connection between Hamiltonian dynamics
and quaternions.
Another possibility is that the authors are interested in the
intersection of the symplectic group with the unitary or orthogonal
group. In this case both symmetric and antisymmetric forms appear.
In fact, these two possibilities are related since maximal
compact subgroup of SU^*(2N) is the unitary-symplectic group
USp(2n), and similar relationship holds between SO^*(2N) and U(N).
For more details, see chapter 6 in the book by Gilmore mentioned
previously.
In any event, one should realize that it is the invariance of a
given bilinear antisymmetric form which crucial to the definition
of a symplectic group.
--
Dave Schneider
University of Illinois at Urbana-Champaign
Center for Supercomputing Research and Development
367 Computer and Systems Research Laboratory
1308 W. Main Street
Urbana, IL 61801-2307
MC-264
phone : (217) 244-0055
fax : (217) 244-1351
E-mail: schneid@csrd.uiuc.edu
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