🚀 go-pugleaf

logajan@ns.network.com (John Logajan) writes:

>chuck@coplex.com (Chuck Sites) writes:
>>At what point does a hydrino become a neutron?               

>Never.
>A neutron has a rest mass of 939.573 Mev/c^2
>A proton has a rest mass of  938.280 Mev/c^2
>An electron has a rest mass of 0.511003 Mev/c^2

>If a MKF electron/proton pair didn't lose any energy/mass at all to radiation
>then it would come out to be 939.573 - 938.28 - 0.511 = 0.782 Mev's too light
>to be a neutron.  But, of course, MKF claim each transistion does radiate,
>thus in a fall from n=ground to n=1/210 (an orbit the size of the proton radius)
>the MKF electron/proton pair lose an additional 0.6 Mev.

And the winner is John!  A neutron decays in 15.5 Hrs, by
               n -> p + e- + (anti)v_e 
because the neutron is 0.782ev too heavy and a half-spin in the wrong
direction! I was half-heartedly kidding about neutron production from
a hydrino collapse. Yet by electron capture,
                p + e- -> n + v_e
I'm not going to suggest cold EC. MKF is basically the Borh model for one
electron atoms taken to the extreem.  It's the exact oposite of ionization,
electron orbital collapse.  The difference between an electron spiraling
into the nucleus and MKF is that, MKF treats the photon as a wave and  
certain syncronous components of that wave are trapped by the electron
charge density.  If the phase of the trapped photon hits C, that
component of the photon is emitted, and the shell collapses. It's 
pure and simple a 1/n Bohr model (a Bohr model all the way down to
the nucleus).   

The implications are obvious, an absorbtion spectrum should be seen
for 1/n and I understand Mill's claims that these lines have been 
seen in an UV sky survey.  I'm skeptical that there is anything to
this, but I'll see what I can find in the library. 

Have fun,
Chuck Sites
chuck@coplex.com