Re: A New Solution to the Twins Paradox, and Others

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#6220

From: nessunoic
Date: Thu, 01 Nov 2007 13:44

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one last note if you allow me.
As someone told here and as many books on relativity assert:

For the entire outward and return parts of the trip, A does
"observe" B's clock running slow. Here B is moving back and forth and
A is staying still on earth all the time.

Note the word used - "observe".
And this is this word that is wrong here and mislead all of us. A does
not observe it but he calculates/assumes it to be happening to
preserve the validity of simultanious with him reality and
simultanious with B reality (all those there-now dots). In real world
A sees 3x slower time flow of B on way away and 3x faster on way back.
Where then the estimation of B's clocks running slower comes from? It
comes from the fact that in 20 A's years only 12 B's years pass.

The thinking of A (estimation of how simultanious with B reality
should look) could be as follows:
B moves 8 light years at speed of 0.8c. It should take him 8/0.8=10
years to cover the distance. But hack he manages to accomplish it in
his 6 years (i can see it in my telescope - the moment he reaches the
star his time shows 6 years passed). How is that possible ?
Well B must be having slow down in time rate of 6years/10years
=0.6 .Yeah of cause. Hm but then the distance of 8 light years ?
Oh well he must be having space contraction so the distance he covers
in 6 his years moving at 0.8c speed is to be 0.8*6=4.8 light years.
Voila his space contraction then must be equal to 4.8/8=0.6
So A estimates B's space be contracted by factor of 0.6 and time be
contracted of the same factor of 0.6. So A's 8 l.y and 10years time
look for B as 4.8 l.y and 6 years of time to cover the distance.

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From:  nessunoic@hotmail.com
Newsgroups: sci.physics.relativity,sci.physics,sci.astro,fr.sci.physique,fr.sci.maths
Subject: Re: A New Solution to the Twins Paradox, and Others
Date: Thu, 01 Nov 2007 06:44:18 -0700
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