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Article #6804Re: THE WAVE MODEL OF LIGHT AND EINSTEINIANA
From: RP
Date: Sat, 02 May 2009 17:43
Date: Sat, 02 May 2009 17:43
62 lines
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5426 bytes
On May 2, 11:38 am, John J <n...@droffats.ten> wrote: > http://www.wired.com/wiredscience/2009/05/extremelaser/ > > I don't know if the above has yet been cited. Perhaps it is relevant to > this thread. It's relevant to past discussions of the photoelectric effect, but it has nothing to do with phase waves and superluminal velocities. Some time back during the course of a discussion about the photoelectric effect I predicted that an extremely high intensity beam would cause photoelectron ejection, even though the frequency of the beam was below the cutoff frequency for the metal surface. This was based upon a complex wave model of the photoelectric effect. Briefly, the theory is that at any given moment any atom is subject to em waves from a virtually infinite number of sources (charges). Ordinarily we call this the thermal radiation background. This background noise is usually incoherent, and thus tends to do no more than to transfer heat energy, which is of course why it's called thermal radiation. However, heat energy is internal kinetic energy, and for the metal surface this involves an amplification or "pumping" of the orbital electron's energies. On average, at normal room temps, these energies are below the work function of the metal surface. Even so, because of the chaos, electrons will evaporate from the surface, just as molecules evaporate from the surface of a liquid. The velocity distribution fits a Bell curve. So in the real world (as opposed to the modified forms of reality presented in some texts), there are electrons being ejected from the surface even before we shine a light beam on it. These evaporated electrons form a "space charge", which, because of the lack of a direct source of light above the cutoff frequency, already seem defy the photoelectric theory of Einstein's. Well, the theory isn't defeated just yet. Thermal radiation is a spread spectrum, of which the infrared region just happens to be the peak. So there is already light impinging on the surface at frequencies above the cutoff frequency. Now by the wave theory, this means that the surface is pumped. For every electron within the surface that is ejected by thermal radiation, there are electrons who came just a fraction short of gaining enough KE to break free. It is this percentage of the electrons that starts to be ejected when a light beam strikes the surface. Each gains just enough extra energy to go ahead and jump off the surface. These electrons do not absorb an entire photons worth of energy, but just sufficient energy, added to the energy that they already had, to break free. The remainder of the photons worth of energy emitted by the light source becomes just that much more heat energy in the surface, barring the amount of it that is reemitted as em radiation. The energy of the photoelectrons corresponds to the energy of the source photons only because conservation of energy requires it. If these didn't match, then energy will have been lost from or gained by the system. It's just conservation of energy. Now the reason for the frequency dependence is this, the electron in the surface is oscillating wrt positive protons, and what is required is a boost in it's KE of a sufficiently short interval. Longer wavelengths of radiation would tend to accelerate both charges together, in the same direction, or in other words tend to only jiggle the atoms as a whole. Higher frequencies are required to produce opposing forces on these charges, i.e. to split them apart. It's a time limiting contstraint moreso than an energy limiting constraint. For this reason, a very intense beam of coherent radiation of a frequency below the cutoff frequency could still produce sufficient separating forces between these charges. And apparently this has been verified by the experiment that you mention.
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