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"Thomas" <thomas.smid@gmail.com> wrote in message 
news:7b80157e-d871-4366-896d-6554a70a9dd2@a1g2000hsb.googlegroups.com...
| On 27 Apr, 18:33, Craig Markwardt
| <craigm...@REMOVEcow.physics.wisc.edu> wrote:
| > "Androcles" <Headmas...@Hogwarts.physics> writes:
| > > <Loui...@edu.herlufsholm.dk> wrote in message
| > 
 >news:1c5e632b-6dba-4566-8fe1-ccad14fe81ec@p25g2000hsf.googlegroups.com...
| > > |PIONEERANOMALYAND COSMIC DECREASE OF GRAVITY
| > >  The modified Hubble-law
| >
| > > | By Louis Nielsen
| > > |http://www.rostra.dk/louis
| >
| > > | THEPIONEER-ANOMALY.
| > > | When all known forces acting on thePioneerspacecrafts are taken into
| > > | consideration, a very small but unexplained force remains.
| >
| > > No it doesn't, the crank Einstein shift was applied where Doppler 
shift was
| > > is
| > > and remains appropriate.
| > > The "unexplained" force is --- ya got ya sums wrong.
| >
| > This statement is incorrect.  If the classical Doppler shift is used
| > instead of the relativistic one, thePioneersolution actually becomes
| > much worse.
|
| The classical (first order) Doppler shift was actually used by
| Anderson et al. in their paper (see Eq.(15) in 
http://arxiv.org/abs/gr-qc/0104064
| ).

The correct Doppler shift is f' = f.(c+v)/c.

The "classical" Doppler shift (as it applies to a medium) is
f' = f. c/(c+v)
Ref:  http://en.wikipedia.org/wiki/Doppler_effect

Both "relativistic" and "classical" would be wrong.

Doppler's full equation is
             c+v
f' = f  * ------
             c+u

Where v the motion of the source relative to the medium
and u is the motion of the observer relative to the medium.
In the absence of a medium f = f . (c+v)/ c applies.

As usual, wackypedia is full of incomplete rubbish.

The "unexplained" force is --- ya got ya sums wrong.