Re: Pound Rebka

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Article #16225

#16225

From: Paul B. Andersen
Date: Tue, 19 Feb 2008 14:11

49 lines
3787 bytes

Androcles wrote:
> 
>  Definitely right off the scale of my bullshit meter, a year on the Moon
>  is exactly the same as a year on Earth and is also a trip around the
>  Sun, the Earth and Moon are together and a year is a unit of time.
> 
> If you use GR to calculate the time on Earth vs the time on the Moon
>  http://en.wikipedia.org/wiki/Gravitational_time_dilation
> 
>  tf = 1,000,000 years
>  gravitational constant G = 6.673E-11 m^3 kg^-1 s^-2
>  Mass of Earth = 5.9736E+24 kg
>  r = 385000 km (distance to Moon)
>  c = 299792.458 km/sec
> 
>  t0 = 994222.168323667

You can't expect Androcles to be able to insert numbers
into an equation and get the right answer.
Androcles doesn't understand what the equations mean,
so he uses them wrongly.

The correct answer is:
While an observer on the Earth measure 1,000,000 years,
an observer on the Moon (if we ignore the mass of the Moon)
would measure 1000000.0006797 years.
That is approximately 6 hours more than the observer on the Earth.

Let's ignore the wildly wrong numbers, and enjoy
the beautiful logic of this statement:

> An observer on Earth measures the Moon making ~6 more
> orbits around the Sun in a thousand years, as prophesied
> by Einstein. You'd think someone would notice by now.

Hilarious, no? :-)

In the unlikely (1) event that the reader doesn't get what
is hilarious, it is that all observers obviously will
count the same number of orbits of the Moon.
It is the orbital period they will disagree about.

(1) Unless the reader is Sue, Henri, Androcles or
     a few other cranks.

-- 
Paul

http://home.c2i.net/pb_andersen/

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From: "Paul B. Andersen" <paul.b.andersen@hiadeletethis.no>
Newsgroups: sci.physics,sci.physics.relativity,rec.org.mensa,fr.sci.physique,sci.astro
Subject: Re: Pound Rebka
Date: Tue, 19 Feb 2008 15:11:41 +0100
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