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Article #16266

Re: Pound Rebka

#16266
From: Eric Gisse
Date: Mon, 11 Feb 2008 22:15
53 lines
3719 bytes
On Feb 11, 1:09 pm, HW@....(Dr. Henri Wilson) wrote:
> On Mon, 11 Feb 2008 21:53:42 +0100, "Paul B. Andersen"
>
>
>
> <paul.b.ander...@guesswhatuia.no> wrote:
> >Max Keon skrev:
> >> "Eric Gisse" <jowr...@gmail.com> wrote in message
> >>news:cf7fd5a6-005e-4d73-aef9-ba788194923d@s8g2000prg.googlegroups.com...
> >How did you arrive at this remarkable conclusion?
> >It is wrong.
>
> >f_h/f_o = (1-(GM/r)/c^2)/(1-(GM/R)/c^2)~= 1-(GM/r)/c^2 + (GM/R)/c^2
> >where:
> >   f_h = frequency of gamma photon at the top of the tower
> >   f_o = frequency of gamma photon at the bottom of the tower
> >   r = the distance centre of the Earth - top of tower
> >   R = radius of the Earth (at the bottom of the tower)
>
> >  r = R + h, h = height of tower
> >  f_h/f_o ~= (1 + ((GM/R)/c^2)(1 - R/(R+h))
> >  When h/R << 1 :
> >  R/(R+h) ~= (1-h/R)
>
> >  f_h/f_o ~= 1 + ((GM/R)/c^2)(h/R)
> >  g = GM/R^2
>
> >  f_h/f_o ~= 1 + gh/c^2
> >  Which is in accordance with the Pound & Rebka experiment.
>
> ...which is exactly in acordance with BaTh.
>
> PE (per unit mass) at top = gh.
> Increase in KE as light falls = [1/2(c+v)^2]-[1/2c^2]  = ~ cv

So light has unit mass? Or did you forget that kinetic energy is
proportional to mass?

>
> So: v = gh/c
>
> f1/f_0 = (c+v)/c = [c + (gh/c)]/c = 1 + gh/c^2
>
> Strange, eh?...and much, much simpler than Einstein's nonsensical method of
> inserting a gradient into space in order to maintain a constant light speed.

Poor stupid Ralph Rabbidge still can't separate cause and effect.
Constant light speed /causes/ what you call the gradient.

>
> Henri Wilson. ASTC,BSc,DSc(T)www.users.bigpond.com/hewn/index.htm
>
> Einstein's  Relativity is easy to understand if one has the IQ of a parrot and a gullibility index >0.95.
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From: Eric Gisse <jowr.pi@gmail.com>
Newsgroups: sci.physics, sci.physics.relativity, rec.org.mensa, 
 fr.sci.physique, sci.astro
Subject: Re: Pound Rebka
Date: Mon, 11 Feb 2008 14:15:24 -0800 (PST)
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