🚀 go-pugleaf

"Eric Gisse" <jowr.pi@gmail.com> wrote in message
news:b4e56b7e-87dc-4a55-ad61-029ac621b246@e6g2000prf.googlegroups.com...
> On Jan 23, 9:15 pm, "Max Keon" <maxk...@optusnet.com.au> wrote:
>> Eric Gisse wrote:
>>> Max Keon wrote:
---
>>>> Every natural oscillator is affected by every bit of matter in
>>>> the universe. If the mass of the currently visible universe is
>>>> i.e. 5e+56 kilograms, and all of that mass resided in a thin
>>>> shell at the visible extremes, at a 13 billion light year radius,
>>>> or 1.23e+26 meters, clock running speed is  t' = t/(G*M/(c^2*r))
>>>>  t' = 3.32e-4 of what it would be in a universe where only the
>>>> clock exists.
>>>
>>> When you learn to stop pulling equations out of your ass, let me
>>> know and this can continue.
>>
>> I chose to use the equation in the above format because
>>  t' = t*(G*M/r))

In highlighting the change from "t/" to "t*" I accidentally
removed "c^2" from the equation, which was supposed to read
 t' = t*((G*M/r)/c^2) . It's now set out so that gravitational
potential is more obviously divided by c^2. "t" is the time unit
of course. Perhaps that helps with your confusion.

 t' = t*(G*M/(c^2*r)) naturally gives the same result.

>>     generates numbers large enough to frighten you
>> away. We can do it your way if you like. t' is of course the
>> clock slowing rate per (whatever time unit you want).

> Stop pulling equations out of your ass if you want people to listen to
> you.

Now that any misunderstanding has been cleared up, you will no
doubt agree with this next paragraph from my previous post that
you snipped.

>> You will no doubt recognize the time slowing difference between
>> the Earth surface and the GPS according to that equation.
>> A clock at 6378000 meter radius loses 6.937e-10 sec/sec.
>> A clock at 26570000 meter radius loses 1.665e-10 sec/sec.
>> The difference is 5.272e-10 seconds per second or 4.5422e-05
>> seconds per sidereal day. You're happy with that?

You've been around here long enough to immediately recognize that
number as the time difference per sidereal day between Earth and
GPS satellite based clocks, which is according to GR. The
equation I've used is obviously correct.

>> The actual clock rates are per  t' = t + t*(G*M/(r*c^2))
>> Each second on the Earth's surface is 1.0000000006937 seconds
>> according to a clock that's unaffected by Earth's gravity, and
>> is 1.0000000001665 seconds at a GPS radius.

Is anything there a problem to you?

>> Consider an Earth diameter and Earth mass sphere where all of
>> the matter is spread uniformly throughout a thin outer shell. One
>> second for a clock at the center would be
>>  t' = t + t*(G*M/(r*c^2)) = 1.0000000006937 unaffected clock
>> seconds. That will be the case regardless of where the clock is
>> placed within the shell. You can do the calculations.

Do you agree that a clock will run more slowly anywhere within a
hollow Earth than it will anywhere outside the shell? And do you
also agree that the internal clock will further slow if the shell
radius is reduced?

>> But the clock that's considered free from the effects of Earth's
>> gravity is still affected by the matter in the universe. It's
>> never free to run unaffected by gravity. And that is what
>> demolishes the big bang theory.

The rest is just plain sailing.

>> Now consider a visible universe diameter sphere, 13 billion
>> light years or 1.23e+26 meter radius, with all of the matter,
>> i.e. 5e+56 kg, contained in a thin outer shell.
>>  t' = t + t*(G*M/(r*c^2)) = 3014. A truly free clock ticks 3014
>> seconds in one second according to the universe housed clock.
>>
>> Then take the clock back to the early universe, 300000 years
>> after the big bang. Allowing for as much as a 20 times light
>> speed initial expansion, gives a shell radius of 5.68e+22 meters.
>> The mass of the universe remains constant. The clock now ticks 1
>> second per 6523866 free clock seconds. That's 2165 times slower
>> than today's clock.
>>
>> The same applies for the spectral line generating oscillators at
>> the time. They are affected in exactly the same way as the atomic
>> clock oscillator. Spectral lines are redshifted ENORMOUSLY before
>> the expansion is even considered.
>>
>> Spectral line generating oscillator rates increase as the
>> universe evolves.
>>
>> Here's how the zero origin universe accommodates the CMBR,
>>  http://members.optusnet.com.au/maxkeon/cmbr.html
>> You should be able to recognize the real universe by now.

This is how the CMBR compares with big bang's prediction. Error
bars won't help much here, will they.

                   .
                .     .
               .       . Actual CMBR
              .         .
            .             .
         .                   .


       .......................... CMBR as predicted by
                                  the big bang theory.


-----

Max Keon