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Article #3986Re: What's a manifold?
From: Dale Hall
Date: Thu, 05 Nov 1992 17:31
Date: Thu, 05 Nov 1992 17:31
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5814 bytes
In article <1992Nov5.060400.14203@CSD-NewsHost.Stanford.EDU> pratt@Sunburn.Stanford.EDU (Vaughan R. Pratt) writes: >In article <1992Nov5.035214.25991@galois.mit.edu> tycchow@riesz.mit.edu (Timothy Y. Chow) writes: >> >>Well, this definition has the advantage of being easily motivated and >>concrete, but as people started studying manifolds more deeply they >>found that it was often a nuisance to have to be tied to a particular >>function f to define their manifolds. There were certain geometric >>properties of manifolds that were "intrinsic" to the surface and didn't >>really depend on the function f in any essential way. It seemed that >>what was needed was a way of defining manifolds without having to pick >>a space R^n for the manifold to live in and specify an explicit function. >> >>Hence the modern approach to manifolds is to define them as objects in >>their own right, without reference to a space that they're imbedded >>in. This is what motivates the definition that John Baez gives. >>Notice that he doesn't require the manifold to live in some R^n. The >>extra abstraction is a small price to pay for the simplification and >>logical clarity that it yields, as you will appreciate if you study the >>subject more deeply. Similarly, smooth manifolds and algebraic >>varieties (and later schemes) are nowadays defined without making them >>live in R^n. > >Ah, now this is starting to sound very interesting and helpful. What I >don't understand here is how "living in R^n" is of itself creating >complexity and obscurity. I can see that the arbitrariness of f might >get in the way. But where does the complexity and obscurity creep in >if for example we define a manifold to be a smooth retract of an open >subset of R^n? (This is essentially taking the existence of tubular >neighborhoods as definitive of manifolds, and is how Bill Lawvere likes >to think of them.) The problem, as I see it, with thinking of manifolds as living in some ambient Euclidean space, is that it causes confusion when the manifold arises full-grown from the head of Zeus, as it were. For instance, imagine a manifold M (maybe it's in R^n), and you have some notion of symmetry that applies to M. Further, you know that (for instance) for any x in M, the set of all things related to x by symmetry (for the sake of discussion, let's call it the cohort of x [non-standard terminology here]) is particularly nice: the cohort of x is always a circle, say, and all of the symmetry operations treat nearby cohorts in a continuous fashion. That is, if operation \theta sends x to the "circle element" x_\theta, and if y is near x, then the operation \theta yields y_\theta which is similarly near x_\theta (I'm being purposely informal about things that can indeed be made precise). If the symmetry is regular in a suitable sense, then one can construct a manifold M/~ where ~ is the equivalence relation defined by x ~ x' if x and x' belong to the same cohort. (I mean, you can always define the quotient of a space w.r.t. an equivalence relation, but in this case the quotient inherits a manifold topology) Now, the symmetry may not apply to all of R^n, so you're left with M/~ that is homeless in the sense of not having a Euclidean space to reside in. If your definition of manifold forces you to think only of manifolds within Euclidean spaces, then you're stuck until you can find an equivariant embedding of M in some R^m (perhaps different from its earlier home of R^n). A more insidious problem arises when you think of manifolds that are thought of as the zero-set of some smooth function f: R^n --> R^k. If you use the implicit function theorem to guarantee that you have a real-live manifold (i.e., you restrict the Jacobian to have rank k along the zero set),then you have condemned your manifolds to a very nearly trivial existence from some perspectives: each will have its characteristic (Stiefel-Whitney, Pontrjagin, Chern) classes <<all>> zero, for the reason that the normal bundle of the manifold in R^n will be trivial, since it is the pullback of the normal bundle of 0 in R^k (a patently trivial bundle if ever there was one) and thus the tangent bundle will be stably trivial. No projective spaces RP^n or CP^n, no cobordism theory because every manifold you ever see will bound (in the next higher dimension). Pretty dull, if you ask me. If you're a complex kind of guy, you'll likely stick to holomorphic functions, and will notice that you never ever see compact manifolds, since no compact complex manifold embeds holomorphically in C^n. Even the Riemann sphere, that old friend from complex analysis, stubbornly refuses to visit. Not to mention the global picture of Riemann surfaces. My sense is that it is the notion of freeing manifolds from the bonds of the Euclidean captors that has enabled the theory to blossom as it has. That other stuff? Yeah, it's important too, but it could have been accomplished with embedded manifolds, even if it would have been clumsy. My opinion only. Dale.
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Newsgroups: sci.physics,sci.math Path: arc1-ca.pugleaf.net!sparky!uunet!charon.amdahl.com!pacbell.com!decwrl!ames!agate!linus!linus.mitre.org!linus!wdh From: wdh@linus.mitre.org (Dale Hall) Subject: Re: What's a manifold? Message-ID: <1992Nov5.173144.226@linus.mitre.org> Followup-To: sci.math Summary: abunchastuff Keywords: manifolds Sender: Dale Hall Nntp-Posting-Host: linus.mitre.org Organization: Research Computer Facility, MITRE Corporation, Bedford, MA References: <1992Nov5.004804.24757@galois.mit.edu> <1992Nov5.035214.25991@galois.mit.edu> <1992Nov5.060400.14203@CSD-NewsHost.Stanford.EDU> Distribution: na Date: Thu, 5 Nov 1992 17:31:44 GMT Lines: 89