🚀 go-pugleaf

>Question: in C, if one declares char a[I][J], is there anything in the

Remember:  a[i] really means *(a+i) using the rules for pointer addition.
a[i] is a macro construct.

So a[i][j] really works out to *((char *)&*(a+i) + j), I think.
So "a" has an "element size" if J characters in this context.
If we declare "char *b = a;" then the following should work:

        a[i][b] == *((b+i*J) + j)

and

        &a[i][b] == ((b+i*J) + j)

In as much as linear array elements are contiguous, so are multi-
dimentional array elements, since they are simply arrays of arrays.

Check K&R for details (see pointer arithmatic, and multinet-dimentional
arrays).  I have no idea what ANSI has to say on the subject.

-bruce